PROBLEMAS DE FÍSICA

Determinar T1 y T2

ΣFx = 0

T1 Cos 10° + T2 Cos 40° = 0

1) 0.9848T1 + 0.7660T2 = 0

ΣFy = 0

T1 Sen 10° + T2 Sen 40° -1177.2N

2) 0.1736T1 + 0.6427T2 = 1177.2N

Se forma un sistema de ecuaciones:

0.9848T1 + 0.7660T2 = 0

0.1736T1 + 0.6427T2 = 0

Se despeja a T1

T1 = 0.7660/0.9848

T1 = 0.777T2

Se sustituye en la ec 2)

0.1736 (0.777T2) + 0.6427T2 = 1177.2N

0.1348T2 + 0.6427T2 = 1177.2N

0.7775T2 = 1177.2N

T2= 1514.08N

T1 = (0.777)(1514.08N)

T1 = 1176.44N